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3 years ago

Help me with math questions urgent Thanks

Mathematics

1 answer:

aleksandrvk [35]3 years ago

7 0

Answer: x = 2.65, y = 3.81

Step-by-step explanation:

ABC similar to PQR

1) Find the ratio of corresponding sides

2) Use that ratio to find values for x & y

1) Side AB = 2.76cm & Side PR = y cm

Side BC = x cm & Side RQ = 3.66 cm

Side CA = 3 cm & Side QP = 4.14 cm (both lengths given)

Can match 3 to 4.14 & ratio of sides in ABC to PQR= 3 /4.14

Length of sides ABC = 3/4.14 times the length of sides PQR

2) x = (3 / 4.14) * 3.66 = 2.65

Now solve for y, ABC to PQR: 2.76 = (3 / 4.14) (y )

equality property (both sides) & inverse operation to isolate y : . 2.76 ÷ (3 / 4.14) = (3 / 4.14 ) ÷ (3 / 4.14) (y)

2.76 * (4.14 / 3) = 3 / 4.14 * (4.14 / 3) (y)

(2.76 * 1.38 ) = 3.81 = y

Scale Factor Method: Determine the Multiplier

Small to Big or Big to Small ➜ Be sure not to switch

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Step-by-step explanation:

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Width = 2x²

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3 years ago

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Alecsey [184]

Step-by-step explanation:

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3 years ago

1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio

BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image $(x,y)\rightarrow Image(kx,ky)$

where $k$ represents the scalar factor.

We can find value of $k$ for the given co-ordinates by finding the ratio of $x$ or $y$ co-ordinates of the image and pre-image.

$k=\frac{Image}{Pre-Image}$

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of $k=\frac{-60}{-12}=5$

or $k=\frac{15}{3}=5$

As we get $k=5$ for both ratios i.e of $x$ and $y$ co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image $(-2,-7)\rightarrow$ Image $((-2\times5),(-7\times 5))$

Pre-Image $(-2,-7)\rightarrow$ Image $(-10,-35)$ (Answer)

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3 years ago

The "cold start ignition time" of an automobile engine is being investigated by a gasoline manufacturer. The following times, in

Nezavi [6.7K]

Answer:

1. Sample Mean = 2.50

2. Sample Variance = 1.35

3. Standard Deviation = 1.16

Step-by-step explanation:

Note: As this question is not complete, similar can be found on internet where following are asked to calculate and here I will calculate these as well.

1. Sample Mean.

2. Sample Variance.

3. Sample Standard Deviation.

So, for sample mean to calculate from the given data points. We need to apply to following formula to calculate sample mean.

Sample Mean = (X1 + X2 + .... + XN) divided by Total number of data points.

Sample Mean = (0.17 + 1.94 + 2.62 + 2.35 + 3.05 + 3.15 + 2.53 + 4.81 + 1.92) divided by (9).

Sample Mean = 2.50

Likewise, from the answer of sample mean we can calculate sample variance by following steps.

Solution:

1. Subtract the obtained mean from each of the data point given.

(0.17 - 2.50) = -2.33

(1.94 - 2.50) = -0.56

(2.62 - 2.50) = 0.12

(2.35 - 2.50) = -0.15

(3.05 - 2.50) = 0.55

(3.15 - 2.50) = 0.65

(2.53 - 2.50) = 0.03

(4.81 - 2.50) = 2.31

(1.92 - 2.50) = -0.58

2. Square each of the differences obtained in step 1.

$-2.33^{2}$ = 5.43

$-0.56^{2}$ = 0.31

$0.12^{2}$ = 0.01

$-0.15^{2}$ = 0.02

$0.55^{2}$ = 0.30

$0.65^{2}$ = 0.42

$0.03^{2}$ = 0.01

$2.31^{2}$ = 5.34

$-0.58^{2}$ = 0.34

3. Sum all of these squares.

(5.43 + 0.31 + 0.01 + 0.02 + 0.30 + 0.42 + 0.01 + 5.34 + 0.34) = 12.18

4. Divide 12.18 by (n-1), where n = 9.

Sample Variance = 12.18/9 = 1.35

Now, by using sample variance, we can calculate standard deviation with easy simple steps.

So, in order to find standard deviation, we just need to take the square root of sample variance that we have already calculated above.

Standard Deviation =  $\sqrt{1.35}$  = 1.16 

Good Luck!

6 0

3 years ago