Okay so like, all you've gotta do is multiply 567 by 48 & add 1250. Leaving you with the answer of 28,466
There were 300 jelly beans in the bag. that includes the green ones.
[x-1]=5x+10
We have two equations:
1) x-1=5x+10
x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4
2) x-1=-(5x+10)
x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2
we have two possible solutions:
solution₁; x=-11/4
solution₂: x=-3/2
we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4 - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4 + 10
[-15/4]=(-55+40) /4
15/4≠-15/4 This solution don´t work.
2) x=-3/2
[x-1]=5x+10
[-3/2 - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2 + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.
Therefore:
Answer: x=-3/2.
Answer:
<em>a) </em>
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<em>b) The coordinates of P are</em>
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Step-by-step explanation:
<u>Translation</u>
The dashed line shows the graph of the function
This function has a maximum value of 1, a minimum value of -1, and a center value of 0.
a)
Graph G shows the same function but translated by 2 units up, thus the equation of G is:
b) The coordinates of P correspond to the value of
The value of G is
Since
The coordinates of P are
With the mean and range, we can estimate the weights of the smallest and largest animals in each group.
For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]
<h3>
Which conclusions can be made with the given information?</h3>
We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.
- From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
- And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg
(Assuming a normal distribution).
Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:
- The largest dog weights 32kg + 45kg/2 = 54.5kg
- The smallest dog weights 32kg - 45kg/2 = 9.5kg
(again, assuming a normal distribution).
If you want to learn more about means and ranges:
brainly.com/question/14532771
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