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alexdok [17]
1 year ago
6

URGENT!!! 100 POINTS WILL GIVE BRAINLIEST, PLEASE DONT JUST PUT SOMETHING FOR POINTS a nail salon is looking to open a new locat

ion. The rent at Location A is $1200 per month and they will charge $45 per manicure/pedicure. The rent at Location B is $1800 per month and they will charge $60 per manicure/pedicure. How many manicure/pedicure will they need to do to make the same profit at each location?
a. Write a let-statement defining your variable.

b. Write an equation in one variable to solve.

c. Show work to solve the equation.

d. Write a sentence for your final answer.​
Mathematics
1 answer:
allsm [11]1 year ago
7 0

Answer:

\textsf{a) \quad Let $x$ be the number of manicure/pedicures per month}.

\textsf{b)} \quad 60x-1800=45x-1200

\textsf{c) \quad $x=40$}

d)  The two salons will need to do 40 manicures/pedicures each month to make the same profit at each location per month.

Step-by-step explanation:

<h3><u>Part (a)</u></h3>

<u>Definition of the variables</u>:

  • Let x be the number of manicure/pedicures per month.
  • Let y be the total profit (n dollars).

<h3><u>Part (b)</u></h3>

Create an equation for each location.

<u>Location A</u>

The rent at Location A is $1200 per month and they will charge $45 per manicure/pedicure:

\boxed{y = 45x - 1200}

<u>Location B</u>

The rent at Location B is $1800 per month and they will charge $60 per manicure/pedicure:

\boxed{y = 60x - 1800}

To determine the number of treatments the two salons will need to give to make the same profit at each location, substitute the second equation into the first equation:

\boxed{60x-1800=45x-1200}

<h3><u>Part (c)</u></h3>

Solve the equation from part (b):

\implies 60x-1800=45x-1200

\implies 60x-1800-45x=45x-1200-45x

\implies 15x-1800=-1200

\implies 15x-1800+1800=-1200+1800

\implies 15x=600

\implies 15x\div 15=600 \div 15

\implies x=40

<h3><u>Part (d)</u></h3>

The two salons will need to do 40 manicures/pedicures each month to make the same profit at each location.

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