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Nikitich [7]
1 year ago
12

X - 5y = 10; (0, -2) Group of answer choices no yes

Mathematics
1 answer:
mr Goodwill [35]1 year ago
6 0
  • Yes, this linear equation is correct on point (0,-2).

Given that:

  • The linear equation

         x - 5y = 10;

  • The point

        (0, -2)

To find

  • We have to prove LHS = RHS

So, according to the question

We have,

The linear equation,

         x - 5y = 10; and point is (0,-2)

From equation,

         x - 5y = 10

Take the left part of given linear equation,

         LHS = x - 5y

Now, putting the values, x = 0 and y = -2.

Then, we will be get.

                = x - 5y

                = (0) - 5 ×(-2)

                = - 5 × -2

                = 10.

So, we can say that

          LHS = RHS.

Where,

           LHS = Left Hand Side.

           RHS =  Right Hand Side.      

We can solve that linear equation in other way,

When we put x = 0, we get y = -2.

So, if we put x = 1, we get y = -9/5.

Similarly, if x = 2, then y = -8/5.

Now, we can say that points (0,-2), (1,-9/5) and (2,-8/5) are lie in the linear equation x - 5y = 10.

To learn more about linear equation, please click on the link;

brainly.com/question/13738061

#SPJ1

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Answer:

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Step-by-step explanation:

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Hope This Helps :)

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Create a list of steps, in order, that will solve the following equation. 2(x+3/4)^2-5=123
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Step-by-step explanation:

2(x+\frac{3}{4})^2-5=123

1. Add 5 to both sides.

5+2(x+\frac{3}{4})^2-5=123+5

2(x+\frac{3}{4})^2=128

2. Divide both sides by 2.

\frac{2(x+\frac{3}{4})^2 }{2}=\frac{128}{2}

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3. Take the square root of both sides.

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4. Subtract \frac{3}{4} from both sides.

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