Answer:
She forgot to add the zero when she multiplied 27 x 50
Step-by-step explanation:
If you need one ask me I can try my best to explain
Answer:
-3.45+5.1=1.65
Step-by-step explanation:
You could use a calculator (just sayin)
Answer:
Step-by-step explanation:
The given data is 11, 77, 35, 5, 76, 34, 89, 92, 22
The total number of items in the data is 9. The width of each class interval would be gotten by dividing the difference between the minimum and maximum items in the data by the number of class intervals. From the information given,
Minimum item = 5
Maximum item = 92
Difference = 92 - 5 = 7
Class width = 87/10 = 8.7
By approximation, it is closest to 10
Therefore, the appropriate class group is 0 to 10
The answer is 1506 it is this because if you add th number you will get it
Answer:
For Lin's answer
Step-by-step explanation:
When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.
Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.
Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.
