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Ivan
1 year ago
6

What is a number that when you divide it by 2 and subtract 3.8 from the quotient, you get 7?

Mathematics
1 answer:
Black_prince [1.1K]1 year ago
5 0

Let the number x.

Then the number divided by 2 gives

\frac{x}{2}

Subtract 3.8 from the quotient gives

\frac{x}{2}-3.8

Hence,

\frac{x}{2}-3.8=7\begin{gathered} \frac{x}{2}-3.8=7 \\ \frac{x}{2}=7+3.8=10.8 \\ \Rightarrow x=2\times10.8=21.6 \end{gathered}

x = 21.6

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Several intervals can be combined into one region using the "set union" operation, ∪∪, which is represented as "u" in webwork. f
alekssr [168]

Write the set of points from  -6 to 0 but excluding  -4  and 0 as a union of intervals

First we take  the interval  -6 to 0. In that -4  and 0 are excluded.

So we split the interval -6 to 0.

Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.

Interval becomes [-6,-4) . It says -6 included but -4 excluded.

Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets

(-4,0)

Now we take union of both intervals

[-6,-4) U (-4,0)  --- Interval from  -6 to 0 but excluding  -4  and 0



7 0
3 years ago
Verifique se os numeros 15,20 e 30 sao diretamente proporcionais aos numeros 24,32 e 48
Vikki [24]

We are given to check

whether these numbers are proportional

we know that any set of numbers are proportional when their ratios are equal

so, firstly we will ratios

First set of numbers:

We are given first set of numbers as 15 , 20 and 30

so, it's ratio is

15:20:30

now, we can simplify it

5\times 3:5\times 4:5\times 6

Since, common factor is 5

so, we can cancel 5

and we get

3:4:6

Second set of numbers:

We are given first set of numbers as 24 , 32 and 48

so, it's ratio is

24:32:48

now, we can simplify it

8\times 3:8\times 4:8\times 6

Since, common factor is 8

so, we can cancel 8

and we get

3:4:6

We can see that both sets of numbers are having same ratios

so, they are proportional.........Answer


4 0
3 years ago
Segment BC is a midsegment of triangle TUV. What is the length of segment VC? (A)a (B)2b (C)b (D)c
Ganezh [65]
It would be twice whatever the midsegment equals.
7 0
4 years ago
If shapes have at least one pair of right angles do they have one pair of perpendicular sides
Margaret [11]
If shapes have at least one pair of right angles, they do have one pair of perpendicular sides (True).
7 0
4 years ago
I need help!! Solve -8s-4&gt;3s+3<br> Will mark brainliest!!
iVinArrow [24]

-7/11

Step-by-step explanation:

-8s-4>3s+3=

-8s-3s=3+4

-11s=7

s=-7/11

5 0
3 years ago
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