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4 years ago

Given the three side lengths, how can you tell if a triangle is a right triangle?

2 answers:

8 0

if the sides satisfy the pythagorean’s theorem(a^2+b^2 = c^2). a and b being the legs and c being the hypotenuse. just plug in and solve. :)

valentina_108 [34]4 years ago

3 0

<h3>The sample response from Edge2020 is:</h3>

Square all side lengths. If the longest side length squared is equal to the sum of the squares of the other two side lengths, then it is a right triangle.

Hope this helps :)

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Suppose that the speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles p

denis23 [38]

Answer:

A) $X \sim N(68 , 25)$

B) the probability that is traveling more than 70 mph is 0.3446

C) the probability that it is traveling between 65 and 75 mph is 0.6449

D) 90% of all cars travel at least 56.85 mph fast on the freeway

Step-by-step explanation:

The speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles per hour.

Mean = $\mu = 68 mph$

Standard deviation = $\sigma = 5 mph$

A) X ~ N( _____, _______ )

In general $X \sim N( \mu , \sigma^2)$

$\mu = 68 mph$

$\sigma = 5 mph$

$\sigma^2 = 5^2 = 25$

So, $X \sim N(68 , 25)$

B) If one car is randomly chosen, find the probability that is traveling more than 70 mph.i.e.P(X>70)

So, $Z = \frac{x-\mu}{\sigma}\\Z=\frac{70-68}{5}$

Z=0.4

Using Z table

P(Z>70)=1-P(Z<70)=1-0.6554=0.3446

Hence the probability that is traveling more than 70 mph is 0.3446

C) If one of the cars is randomly chosen, find the probability that it is traveling between 65 and 75 mph.

P(65<X<75)

$Z = \frac{x-\mu}{\sigma}$

AT x = 65

$Z=\frac{65-68}{5}$

Z=-0.6

AT x = 75

$Z=\frac{75-68}{5}$

Z=1.4

Using Z table

P(65<X<75)=P(-0.6<Z<1.4)=P(Z<1.4)-P(Z<-0.6)=0.9192-0.2743=0.6449

Hence the probability that it is traveling between 65 and 75 mph is 0.6449

D)90% of all cars travel at least how fast on the freeway?

Since we are supposed to find at least how fast on the freeway

So,P(X>x)=0.9

1-P(X<x)=0.9

1-0.9=P(X<x)

0.1=P(X<x)

Z value at 10% =-2.23

So, $Z=\frac{x-\mu}{\sigma}\\-2.23=\frac{x-68}{5}\\-2.23 \times 5 =x-68\\(-2.23 \times 5)+68=x$

56.85 = x

Hence 90% of all cars travel at least 56.85 mph fast on the freeway

8 0

3 years ago

PLEASE ANSWER

marissa [1.9K]

Answer:

The answer Is I think 40

6 0

3 years ago

WILL GIVE BRAINLIEST!1 In the figure below, m <1 = 52. Find m / 2.

erastovalidia [21]

Answer:

Step-by-step explanation:

6 0

3 years ago

12 balls numbered 1 through 12 are placed in a bin. In how many ways can 3 balls be drawn, in order, from the bin, if each ball

Iteru [2.4K]

Answer:

1320

Step-by-step explanation:

There are three "spots" for balls.

__ __ __

For the first "spot," and without replacement, meaning we don't put the balls back, there are 12 choices.

12 __ __

But for the next spot, there are only 11 choices. And for the next, there are only 10!

12 11 10

Since these are independent events, we multiply them together.

12 x 11 x 10 = 1320

There are 1320 possibilities!

How could we do it on the calculator, much faster? The question says "in order," so we know it's a <em>permutation,</em> not a <em>combination.</em> This is the nPr button on the calculator (math -> prb -> 2). Just type in 12 nPr 3 and you get the same answer, 1320.

3 0

3 years ago

Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1

mafiozo [28]

Answer:

(a). y'(1)=0 and y'(2) = 3

(b). $y'(t)=kb2t\cos(bt^2)$

(c). $b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$

Step-by-step explanation:

(a). Let the curve is,

$y(t)=k \sin (bt^2)$

So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value $x_{0}$ which lies in the domain of f where the derivative is 0.