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Naily [24]
4 years ago
13

WILL GIVE BRAINLIEST!!!!!

Mathematics
1 answer:
bagirrra123 [75]4 years ago
8 0
336*2 = 672 for area of the rectangle formed by triangle.


672/48 = 14 for side length. (14*48=672)


14^2 + 48^2 = hypotenuse^2

hyp = 2500^.5 = 50

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A factory worker conducted test on a random sample of 150 products. Of the products tested, 2 were found to have defects.Based o
goblinko [34]
60 would end up as defects
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4 years ago
PLEASE HELP ME WITH BOTH MATH QUESTIONS ASAP!!!!!!!!!
maxonik [38]

Answer:

the one on top=   c=  -12

the bottom one=  f=   -15

Step-by-step explanation:

4 0
3 years ago
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5/6w+21=-1/3(2w-9).
oksian1 [2.3K]
I believe this question logically tells us to find the value of w. The two equations are already equated. Since there is 1 unknown and 1 equation, the system is solvable. The solution is as follows:

5/(6w+21) = -1/3(2w - 9)
5/(6w+21) = -1/(6w - 27)
Cross multiplying the terms:
5(6w - 27) = -1(6w +21)
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7 0
4 years ago
2x - 4y + 7x - 87<br> Helppp
xxTIMURxx [149]

Answer:

9x-4y-87

Step-by-step explanation:

2x-4y+7x-87

9x-4y-87

8 0
3 years ago
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B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

8 0
3 years ago
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