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LekaFEV [45]
1 year ago
8

Mike pent $11. 19 on a bag containing red and blue candie. The bag weighed 11 pound. The red candy cot $1. 29 a pound and the bl

ue candy cot $0. 79 a pound. How much red and blue candy did Mike have?
Mathematics
1 answer:
Olin [163]1 year ago
8 0

Mike bought 5 pounds of red candy and 6 pounds of blue candy.

What is word problem?

 Our comprehensive list of math problems focuses on addition, subtraction, multiplication, division and more specific operations. A math problem is a math question written in one or more sentences that asks a child to apply math knowledge to the "real world." life scenario. This means that children need to be familiar with the vocabulary related to the mathematical symbols they used to understand the meaning of word problems.

Here Mike  spent $11.19 on a bag of red and blue candies and both candies weigh 11 lbs

=>Red candies weigh x lbs

=>Blue candies weigh (11-x) lbs

Here cost of x red candy is

=>$1.29/lb* x lbs of red candy

=> 1.29x

Now ,(11-x) lbs of blue candy costs $0.79 (11-x) = $8.69-0 .79 x

Due to the problem, $8.69 - 0.79 x + 1.29 x = $11.19

or $0.50 x = $11.19 - $8.69 = 2.50 $

or $50 x / 100 = $250 / $100

or $50 x = 250 $

or x = 250/50 = 5, red The candy weighs 5 pounds

The blue candy weighs =11-x=11–5=6 pounds

Therefore mike  bought 5 pounds of red candy and 6 pounds of blue candy.

To learn more about word problem refer the below link

brainly.com/question/21405634

#SPJ4

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6 0
4 years ago
Write a formula for the general term​ (the nth​ term) of the arithmetic sequence below. Then use the formula for
schepotkina [342]

Answer:

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3 years ago
Question in screenshot answer must be in cm
prisoha [69]

Answer:

30.5 cm

Step-by-step explanation:

0 < h ≤ 10 ⇔ Midpoint = 5

10 < h ≤ 20 ⇔ Midpoint = 15

20 < h ≤ 30 ⇔ Midpoint = 25

30 < h ≤ 40 ⇔ Midpoint = 35

40 < h ≤ 50 ⇔ Midpoint = 45

50 < h ≤ 60 ⇔ Midpoint = 55

<u>⇒ </u><u><em>Multiply each corresponding midpoint with it's frequency</em></u>

(5 × 1) + (15 × 4) + (25 × 7) + (35 × 2) + (45 × 3) + (55 × 3) = 610

<u>⇒ </u><u><em>Divide the total of 610 by the frequencies added together</em></u>

610 ÷ (1 + 4 + 7 + 2 + 3 + 3) = 610 ÷ 20 = 30.5

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3 years ago
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vlada-n [284]
2,997.99 would be the whole number :)
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3 years ago
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