Question

Mike pent $11. 19 on a bag containing red and blue candie. The bag weighed 11 pound. The red candy cot $1. 29 a pound and the blue candy cot $0. 79 a pound. How much red and blue candy did Mike have?

Answer 1

Mike bought 5 pounds of red candy and 6 pounds of blue candy.

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Here Mike  spent $11.19 on a bag of red and blue candies and both candies weigh 11 lbs

=>Red candies weigh x lbs

=>Blue candies weigh (11-x) lbs

Here cost of x red candy is

=>$1.29/lb* x lbs of red candy

=> 1.29x

Now ,(11-x) lbs of blue candy costs $0.79 (11-x) = $8.69-0 .79 x

Due to the problem, $8.69 - 0.79 x + 1.29 x = $11.19

or $0.50 x = $11.19 - $8.69 = 2.50 $

or $50 x / 100 = $250 / $100

or $50 x = 250 $

or x = 250/50 = 5, red The candy weighs 5 pounds

The blue candy weighs =11-x=11–5=6 pounds

Therefore mike  bought 5 pounds of red candy and 6 pounds of blue candy.

To learn more about word problem refer the below link

brainly.com/question/21405634

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