1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crazy boy [7]
3 years ago
13

Question in screenshot answer must be in cm

Mathematics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

30.5 cm

Step-by-step explanation:

0 < h ≤ 10 ⇔ Midpoint = 5

10 < h ≤ 20 ⇔ Midpoint = 15

20 < h ≤ 30 ⇔ Midpoint = 25

30 < h ≤ 40 ⇔ Midpoint = 35

40 < h ≤ 50 ⇔ Midpoint = 45

50 < h ≤ 60 ⇔ Midpoint = 55

<u>⇒ </u><u><em>Multiply each corresponding midpoint with it's frequency</em></u>

(5 × 1) + (15 × 4) + (25 × 7) + (35 × 2) + (45 × 3) + (55 × 3) = 610

<u>⇒ </u><u><em>Divide the total of 610 by the frequencies added together</em></u>

610 ÷ (1 + 4 + 7 + 2 + 3 + 3) = 610 ÷ 20 = 30.5

You might be interested in
HELP....PLEASE,USE GEOMETRY!
liberstina [14]

Answer:

18\pi

Step-by-step explanation:

area of the "left most" side disk would be \pi r^{2} = 9\pi

the height of the disk is = 2

thus the area would be 18\pi units cubed

5 0
3 years ago
Read 2 more answers
Sally has three tiles each tile is has a different number on it so he puts the three tires down to make a number each number is
Juli2301 [7.4K]

this would be equal to factorial 3 which is written 3! .

It is 3 * 2 *  1 =  6 numbers answer.

4 0
4 years ago
Help i need to submits this quickly
Gnoma [55]
The slope of the line is -3/4
5 0
4 years ago
Read 2 more answers
- Use the unit circle to evaluate<br> the six trigonometric functions<br> of theta= 4pi
Helen [10]
<h2> The six trigonometric functions, \sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}, \cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}},\tan \dfrac{\pi}{4} =1, \cot \dfrac{\pi}{4} =1, \sec \dfrac{\pi}{4} =\sqrt{2} and \csc \dfrac{\pi}{4} =\sqrt{2}.</h2>

Step-by-step explanation:

We have,

\dfrac{\pi}{4}

To write the six trigonometric functions = ?

\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}

\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}

\tan \dfrac{\pi}{4} =1

\cot \dfrac{\pi}{4} =1

\sec \dfrac{\pi}{4} =\sqrt{2}

\csc \dfrac{\pi}{4} =\sqrt{2}

∴ The six trigonometric functions, \sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}, \cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}},\tan \dfrac{\pi}{4} =1, \cot \dfrac{\pi}{4} =1, \sec \dfrac{\pi}{4} =\sqrt{2} and \csc \dfrac{\pi}{4} =\sqrt{2}.

8 0
3 years ago
Ben earns $9 per hour and $6 for each delivery he makes. He wants to make $155 in an 8-hour workday. What is the least number of
ioda
Find how much he will earn
we know he will earn 8 hours sofirst find how many he earns
9 per hour
8 hou
9*8=72
72+6*numberofdeliveries=155
minus 72
6*numberofdeliviers=83
divide by 6
number of delevieries=13.8
he can't make 13.8, round up to get 14

answer is 14 deliveries

7 0
3 years ago
Read 2 more answers
Other questions:
  • Find the zeros of the function <br> F(x)=x^2-5x+5
    10·1 answer
  • a cookie recipe requires 8 tablespoons of butter. If this recipe is used to bake 30 cookies, how much butter is needed for 75 co
    9·1 answer
  • What is the greatest common factor <br> of 100 and 26
    15·2 answers
  • The height of a projectile in the air t seconds after it is shot can be modeled by the function y = -16t^2 + 3200t + 2, where t
    15·1 answer
  • In a certain mid-size city, 90% of the high school graduates are from public schools
    5·1 answer
  • What is the domain of the square root function graphed below?
    6·1 answer
  • in the graph below what is the unit rate ken paid to rent a go kart create a table to help finding the unit rate
    7·1 answer
  • A water pipe is 4 7/12 feet beneath the surface of the road. What is the elevation of the pipe, in feet, expressed as a decimal?
    12·1 answer
  • Write 186% as a mixed number in simplest form
    14·1 answer
  • Help me plz 20 points to who ever gets it right
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!