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Crazy boy [7]
3 years ago
13

Question in screenshot answer must be in cm

Mathematics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

30.5 cm

Step-by-step explanation:

0 < h ≤ 10 ⇔ Midpoint = 5

10 < h ≤ 20 ⇔ Midpoint = 15

20 < h ≤ 30 ⇔ Midpoint = 25

30 < h ≤ 40 ⇔ Midpoint = 35

40 < h ≤ 50 ⇔ Midpoint = 45

50 < h ≤ 60 ⇔ Midpoint = 55

<u>⇒ </u><u><em>Multiply each corresponding midpoint with it's frequency</em></u>

(5 × 1) + (15 × 4) + (25 × 7) + (35 × 2) + (45 × 3) + (55 × 3) = 610

<u>⇒ </u><u><em>Divide the total of 610 by the frequencies added together</em></u>

610 ÷ (1 + 4 + 7 + 2 + 3 + 3) = 610 ÷ 20 = 30.5

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Solve using substitution <br> x-10y=10<br> x= -10
34kurt
-10 -10y = 10
+10 +10

-10y = 20

20/-10 = -2

Y = -2
4 0
2 years ago
Read 2 more answers
What's 2/5 - 9/10 as a fraction?
elena-s [515]

Answer:

- 1/2

Step-by-step explanation:

turn 2/5 to have the same denominator as 10

2 ( 2 ) = 4

5 ( 2 ) = 10

4/10 - 9/10

= -5/10

simplify

-5/10 = -1/2

hope this helps

4 0
3 years ago
Find the sum or difference <br> 1/2 - 1/14<br> A.3/7<br> B.2/7<br> C.4/7
pogonyaev

Answer:

A.3/7

Step-by-step explanation:

1/2 - 1/14

We need to get a common denominator of 14

1/2 * 7/7 = 7/14

7/14 - 1/14 = 6/14

We can simplify by dividing the top and bottom by 2

3/7

7 0
3 years ago
Suppose a club publishes a newsletter. Expenses are$.50 for printing and mailing each copy, plus$300 total for research and writ
luda_lava [24]

200 copies must be  sold

n= number od newsletters

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300=1,5*n

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0,50*200+300=2*200

100+300=400

400=400



5 0
3 years ago
Read 2 more answers
55 is 40% of what number
Oxana [17]
It is important to do the calculations very carefully. Otherwise there is nothing complicated about this problem.
Let us assume the unknown number = x
Then
40x/100 = 55
40x = 55 * 100
40x = 5500
x = 5500/40
  = 550/4
  = 137.5
So 55 is 40% of 137.50. I hope the procedure is clear to you and in future you can solve such problems on your own without requiring any help from outside.This is the simplest way of solving such problems.



5 0
3 years ago
Read 2 more answers
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