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loris [4]
1 year ago
11

Hello! Would like help on parts a & b. Thanks!

Mathematics
1 answer:
aleksandrvk [35]1 year ago
4 0

Part A

Looking at the graph

we have that

z1 ------> the coordinates are (3,5)

so

the standard form is z1=3+5i

z2 ------> the coordinates are (6,-3)

so

the standard form is z2=6-3i

Find out the distance between them

z2-z1=(6-3i)-(3+5i)

z2-z1=(6-3)+(-3i-5i)

z2-z1=3-8i

Find out the magnitude of the complex number (Applying the Pythagorean Theorem)

\begin{gathered} d_{z1z2}=\sqrt{(3)^2+(-8)^2} \\ d_{z1z2}=\sqrt{73} \end{gathered}

The distance between z1 and z2 is the square root of 73 units

Part B

Find out the conjugate of z2

we have

z2=6-3i

so

Remember that

You find the complex conjugate simply by changing the sign of the imaginary part of the complex number

therefore

The conjugate of z2 is (6+3i)

To find out geometrically change the sign of the y-coordinate (imaginary part) of the complex number (Reflect the given point over the x-axis)

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A shop sells shakes for $2 and doublescoop cones for $3. One day they sold 8 more shakes than scoops, and made $156. How many sh
I am Lyosha [343]

Answer:

x = 36 and y = 28

Step-by-step explanation:

Let she sells x shakes and y doublescoop cones

One day they sold 8 more shakes than scoops, and made $156.

ATQ,

2x+3y = 156 ..(1)

Also,

x = y+8 ..(2)

Put the value of x from (1) to equation (2)

2(y+8)+3y = 156

2y+16+3y = 156

5y = 156 - 16

5y = 140

y = 28

Put the value of y in equation (2)

x = 28+8

x = 36

<em>Hence, they will sell 36 shakes and 28 doublescoop cones.</em>

8 0
3 years ago
Juan’s father is paying for a $45 meal. He has a 10%-off coupon for the meal. After the discount, an 8% sales tax is applied. Wh
leva [86]

Answer:

$43.74

Step-by-step explanation:

will pay= $45

10% of =$45×10/100=$4.5

so, $45-$4.5= $40.5

8% tax= $40.5×8/100 =$3.24

total= $43.74

7 0
3 years ago
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

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Answer:

96

Step-by-step explanation:

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3 years ago
(4+2n^3) + (5n^3+2)
pychu [463]
You just have to combine like terms here
6+7n^3 is the final answer

8 0
3 years ago
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