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adoni [48]
1 year ago
11

Find the distance between points O and V.-2 and 1/2

Mathematics
1 answer:
inn [45]1 year ago
3 0

This problem is about the distance between points, in this case, we have to unidimensional coordinates, that is, point O is at -2, and Point V is at 1/2.

It's important to know that the proper way to find the distance here is by subtraction, we need to subtract the final points and the initial point. In math, such subtraction is called "differential" or "variation", just a fancy name.

\Delta=\frac{1}{2}-(-2)=\frac{1}{2}+2=0.5+2=2.5

<h2>Therefore, the distance from O to B is 2.5 units.</h2>
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5. Sarah made 17 out of 25 free throws during practice. What percentage of free throws did she NOT make? A. 68% B. 58% C. 32% D.
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C. 32%

Step-by-step explanation:

The percent 17 is of 25.

17 of 25 can be written as:

17/25

To find percentage, we need to find an equivalent fraction with denominator 100. Multiply both numerator & denominator by 100

17/25 * 100/100

= (17 * 100/25) * 1/100 = 68/100

Therefore, the answer is 68%

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A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res
AveGali [126]

Answer:

The decision rule is  

Fail to reject the null hypothesis

 The conclusion is  

There is no sufficient evidence to show that  the  designer's claim of a better shoe is supported by the trial results.

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu = 15 \ months

   The sample size is  n =  25

   The sample mean is  \= x  = 17 \ months

   The standard deviation is  s = 5.5 \ months

Let assume the level of significance of this test is  \alpha  = 0.05

    The null hypothesis is  H_o :  \mu = 15

     The alternative hypothesis is  H_a : \mu  > 17

Generally the degree of freedom is mathematically represented as  

         df = n -1

=>       df = 25 -1

=>       df = 24

Generally the test statistics is mathematically represented as

        t = \frac{\= x- \mu }{\frac{s}{\sqrt{n} } }

=>   t = \frac{ 17 - 15 }{\frac{5.5}{\sqrt{25} } }

=>   t =  1.8182

Generally from the student t distribution table the probability of obtaining   t =  1.8182 to the right of the curve at a degree of freedom of df = 24  is  

    p-value  = P(t > 0.18182 ) = 0.4286

From the value obtained we see that  p-value > \alpha hence

The decision rule is  

Fail to reject the null hypothesis

 The conclusion is  

There is no sufficient evidence to show that  the  designer's claim of a better shoe is  supported by the trial results.

7 0
2 years ago
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