Solve the equation below. 1/3 + a = 5/4. A=
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Answer:
No, at alpha equals 0.10, we do not have enough evidence to support the county's claim.
Step-by-step explanation:
We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.
A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.
<em><u>Let </u></em><em><u> = true mean speed of the vehicles.</u></em>
SO, <u>Null Hypothesis</u>, :
30 miles per hour {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}
<u>Alternate Hypothesis,</u> :
> 30 miles per hour {means that the mean speed of vehicles is greater than 30 miles per hour}
The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;
T.S. = ~
where, = sample mean speed of 15 vehicles = 31 mph
s = sample standard deviation = 4.7 mph
n = sample of vehicles = 15
So, <em><u>test statistics</u></em> = ~
= 0.824
<u><em>Hence, the value of test statistics is 0.824.</em></u>
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<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>
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Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.
Answer:
hope it helps you
Step-by-step explanation:
To make such a frequency distribution table, first, write the class intervals in one column. Next, tally the numbers in each category based on the number of times it appears. Finally, write the frequency in the final column. A frequency distribution table drawn above is called a grouped frequency distribution table.
