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patriot [66]
1 year ago
8

Solve each system by elimination. 3x + 2 =10 , 6 +4y = 15

Mathematics
1 answer:
NISA [10]1 year ago
7 0

By elimination, the system of equations, 3x + 2y = 10 , 6x + 4y = 15, has no solutions.

A system of equations is a set of two or more equations which includes common variables. To solve system of equations, we must find the value of the unknown variables used in the equations that must satisfy all the equations.

There are three methods that can be used to solve system of equations.

1. Elimination

2. Substitution

3. Graphing

Using the elimination method, given two equations in x and y, a variable should be eliminated by adding/subtracting the two equations.

First, multiply the first equation by 2.

3x + 2y = 10 ⇒ 6x + 4y = 20     (equation 1)

6x + 4y = 15     (equation 2)

Since the new equation of equation 1 has the same coefficients with those in equation 2, but different constants, then the two lines are in parallel.

Hence, the system of equations has no solutions.

Learn more about solving systems of equations by elimination here: brainly.com/question/28405823

#SPJ4

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A farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant prod
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Answer:

Step-by-step explanation:

Given that a farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant produces

When we consider this graph as a straight line, the two points lying on the line would be

(30, 30) and (34, 28) taking n as horizontal and y vertical

Using two point equation we find that

the equation of the line is

\frac{y-y_1}{y_2-y_1} =\frac{x-x_1}{x_2-x_1}

Substitute the points as x =n

\frac{y-30}{28-30} =\frac{x-30}{34-30}\\y-30 = -0.5(x-30)\\y = -0.5x+45

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7 0
3 years ago
There are 5000 undergraduates registered at a certain college. Of them, 448 are taking one course, are taking two courses, 675 a
olga55 [171]

Answer:

Step-by-step explanation:

Hello!

There are some values missing, so I'll find the probability distribution using others as example. Afterwards you can calculate the ones corresponding to this exercise following the same steps.

Considering there are 5000 undergraduates registered in the college.

465 are taking one course

658 are taking two courses

566 are taking three courses

1877 are taking four courses

1344 are taking five courses

90 are taking six courses

First you have to define the variable of interest. To identify it you have to ask yourself the following question: what is the characteristic of this population that is being measured?

The answer is "the number of courses an undergraduate is taking" and this will be the study variable X

X can take values from 1 to 6 courses.

To calculate the probability of each value of X, you have to divide the "number of students taking Xi courses" by "total number of students registered in the college"

For

X=1

P(1)= 465/5000= 0.093

X=2

P(2)= 658/5000= 0.1316

X=3

P(3)= 566/5000= 0.1132

X=4

P(4)= 1877/5000= 0.3754

X=5

P(5)= 1344/5000= 0.2688

X=6

P(6)= 90/5000= 0.018

For this to be a probability distribution the following condition should be met:

F(X)= ∑P(X) = 1

In this example: 0.093 + 0.1316 + 0.1132 + 0.3754 + 0.2688 + 0.018 = 1

I hope this helps!

7 0
3 years ago
What is the difference between explicit and recursive sequences ?
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