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Hoochie [10]
3 years ago
14

BRAINLIEST PLEASE ANSWER FAST What is 12.5% written as a decimal? 0.00125 0.125 1.25 12.5

Mathematics
2 answers:
Lana71 [14]3 years ago
7 0
.125 because a 100 percent as a decimal is 1.0 90 percent is .9 and 10 percent is .1 so 12.5 percent would be .125
r-ruslan [8.4K]3 years ago
4 0
Your answer is .125.
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There are a variety of methods of data collection. 2 examples include<span> observations, textual or visual analysis (eg from books or videos) and interviews (individual or group).</span>
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Omar deposits $8000 into an account pays simple interest at a rate of 3% per year. how much interest will be paid in the first 5
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The amount of interest that will be paid in the first 5 years is $120.00
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Is 226.08cm to the third power the correct response?
drek231 [11]
Surface Area of a cylinder 2(π•r²)+(2π•r)•h

So

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5 0
3 years ago
In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa
arlik [135]

Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The significance level is 0.05.</em>

<em>The data is:</em>

<em>Brand X: 91, 100, 88, 89</em>

<em>Brand Y: 99, 96, 94, 99</em>

<em>Brand Z: 83, 88, 89, 76</em>

We have to check if there is a significant difference between the absorbency rating of each brand.

Null hypothesis: all means are equal

H_0:\mu_x=\mu_y=\mu_z

Alternative hypothesis: the means are not equal

H_a: \mu_x\neq\mu_y\neq\mu_z

We have to apply a one-way ANOVA

We start by calculating the standard deviation for each brand:

s_x^2=30,\,\,s_y^2=6,\,\,s_z^2=35.33

Then, we calculate the mean standard error (MSE):

MSE=(\sum s_i^2)/a=(30+6+35.33)/3=71.33/3=23.78

Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

M_x=92,\,\,M_y=97,\,\,M_z=84\\\\M=(92+97+84)/3=91

The MSB is then:

s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172

Now we calculate the F statistic as:

F=MSB/MSE=172/23.78=7.23

The degrees of freedom of the numerator are:

dfn=a-1=3-1=2

The degrees of freedom of the denominator are:

dfd=N-a=3*4-3=12-3=9

The P-value of F=7.23, dfn=2 and dfd=9 is:

P-value=P(F>7.23)=0.01342

As the P-value (0.013) is smaller than the significance level (0.05), the null hypothesis is rejected.

There is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

3 0
3 years ago
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aleksklad [387]
0.3(4+8)/-0.1+5/(9.2+13.2)= -35.7767857143
8 0
2 years ago
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