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stiks02 [169]
3 years ago
9

A bathtub holds about 2 hectoliters of water. If 25 liters of water are let down the drain, how many liters of water are still i

n the bathtub?
Mathematics
1 answer:
MArishka [77]3 years ago
5 0
2 hectoliters = 2 × 10 × 10 = 200 liters
<span>200 − 25 = 175 liters</span>
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Answer:

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Step-by-step explanation:

Given polynomials are:

x^5-4x^4+7x^3+8, 9x^3+7x^2-10 and -2x^5+7x^4-3x+8

Now we need to add the given polynomials, then place the answer in the proper location on the grid. Also we need to write answer in descending powers of x.

So let's add them by combining like terms:

x^5-4x^4+7x^3+8+9x^3+7x^2-10-2x^5+7x^4-3x+8

-x^5+3x^4+16x^3+7x^2-3x+6

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Answer:

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Step-by-step explanation:

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umka2103 [35]

The figure on the left side shows the water level is at the 0.5 liter mark, ie half a liter.

1 liter = 1000 mL

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If you poured all the water into the jug on the right (without spilling), then the water level should reach the 500 mL mark. This is the small tickmark exactly halfway between the 400 and 600.

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Answer:

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Step-by-step explanation:

You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.

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  x ≥ 7 . . . . makes the statement true

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1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:

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1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive

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