Answer:
Step-by-step explanation:
oh nice, SOH CAH TOA :P
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
SOH CAH TOA is really helpful, it also reminds me of south pacific for some reason :D
Anyway back to math
we want to find an angle and we have the Hyp and the adj sides
to that angle soooo
let's pick CAH since it's got Adj / Hyp , which we know and will find that unknown angle for us.. :)
Cos(Ф) = Adj / Hyp
Ф = arcCos( adj / Hyp)
Ф = arcCos( 14 /28 )
Ф = arcCos(.5) ( if you happen to be good with trig functions you can already tell what it's going to be :P w/o using the calculator)
Ф = 60 °
1a = 60 °
for 1b we know the opp and they hyp and want to find the angle. So let's use SOH
sin = Opp / Hyp
sin(Ф) = 5/20
Ф = arcSin(5 /20)
Ф = arcSin ( 1/4)
Ф = 14.4775 °
1b = 14 ° ( rounded to nearest degree )
See my previous answer to this same question. the vertical angles have to be right angles
The correct answer is: 3) " x ; 1/2" .
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Explanation:
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Question 1)
g [ f(x) ] = ? ;
→ Given: " f(x) = 1/3 x " ;
→ Given: " g(x) = 3x " ;
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g [ f(x) ] = g(1/3 x) = 3(1/3 x) = 1x = "x" .
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Question 2)
g [ f(1/2) ] = ? ;
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→ Given: " f(x) = 1/3 x " ;
→ f(1/2) = (1/3) * (1/2) = (1*1) / (3*2) = (1/6) ;
→ g [ f(x) ] =
g(1/6) = 3* (1/6) = (3/1) * (1/6) = (3*1) / (1*6) = 3/6 = (3÷3) / (6÷3) = " 1/2 " .
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16 ÷ (4)(2) - 3(2) <span>÷ 2+1
16 </span>÷ 8 - 6 <span>÷ 3
2 - 2
0
Answer: 0</span>
17. B $3.00
18.D 35/36
19.D 89.775