Answer:
Step-by-step explanation:
a) Mark any two points in line a
(0,7) ; (5,-3)
Find the slope
slope = y2 - y1 /x2-x1

Equation: y-y1 = m(x-x1)
y - 7 = -2(x - 0)
y - 7 = -2x
y = -2x + 7 --------> line a
c) equation of line b
(2,-1); slope = -2 {as b line is parallel to line a}
y - y1 =m(x-x1)
y -(-1) = -2*(x - 2)
y + 1 = -2x - 2*-2
y + 1 = -2x + 2
y = -2x + 2 -1
y = -2x +1 ------> equation of line b
The two diagonals intersects at right-angle for a kite
the long diagonal also bisects the short diagonal so QP = PS = QS/2 = 6/2 = 3
QPR is a right-angle triangle with QR at 5 and QR at 3
RP = sqrt (5^2 - 3^) = 4m
A+b=6.1 ---(1)
a-b=1.6 ---(2)
(1)+(2); 2a=7.7
then a=3.85
so b=a-1.6 = 3.85-1.6 = 2.25
so that the two numbers are 2.25 and 3.85
Answer:
hope it will help u in understanding