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IRISSAK [1]
3 years ago
6

If f(x)= 1/3x and g(x)=3x, then what are g * f (x) and g*f(1/2)

Mathematics
1 answer:
MrMuchimi3 years ago
3 0
The correct answer is:  3)  " x ;  1/2" .
_____________________________________________________
Explanation:
_____________________________________________________
Question 1) 

g [ f(x) ] = ? ;

→ Given:  " f(x) = 1/3 x " ;

→ Given:  " g(x) = 3x " ;  
__________________________________
g [ f(x) ] = g(1/3 x) = 3(1/3 x) = 1x = "x" .
__________________________________
Question 2)

g [ f(1/2) ] = ? ; 
__________________________________
→  Given:  " f(x) = 1/3 x " ;

→  f(1/2) = (1/3) * (1/2) = (1*1) / (3*2) = (1/6) ;

→  g [ f(x) ] =  

          g(1/6) = 3* (1/6) = (3/1) * (1/6) = (3*1) / (1*6) = 3/6 = (3÷3) / (6÷3) = " 1/2 "  .
___________________________________________________________ 


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What is the cash payment of a article costing RS.2020 allowing a discount of Rs.20 and levying 13% VAT?​
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The cash payment for the article is RS. 2,260.

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7 0
2 years ago
Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8
vredina [299]

Question:

Consider the sequence of numbers: \frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

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(C) The sequence is arithmetic, where each pair of terms has a constant difference of 3/4 .

(D) The sequence is arithmetic and can be represented by the function

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Answer:

Option B:

The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + \frac{3}{8}  .

Explanation:

A sequence of numbers are

\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Let us first change mixed fraction into improper fraction.

\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}

\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}

\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}

\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding \frac{3}{8} to the previous term.

Hence, the sequence is recursive and can be represented by the function f(n + 1) = f(n) + \frac{3}{8}  .

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EastWind [94]
4,0


that is the ordered pair of the solution:)
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