Step-by-step explanation:
Let the ratio constant be 'x'
Sum of the ratios=3x+5x=8x
First person gets:-
3/8 x 560 = 210
Second person gets:-
5/8 x 560 = 350
The following equation has infinite many solutions
3(2x+1)=2(1+3x)+1
Step-by-step explanation:
An equation has infinite solutions if there is same constant on both sides of the equation.
We will check each equation one by one to find the equation with infinite solutions.
So,
<u>3(2x+1)=2(1+3x)+1</u>
![3(2x+1)=2(1+3x)+1\\6x+3 = 2+6x+1\\6x +3 = 6x +3\\6x-6x+3 = 3\\3 = 3](https://tex.z-dn.net/?f=3%282x%2B1%29%3D2%281%2B3x%29%2B1%5C%5C6x%2B3%20%3D%202%2B6x%2B1%5C%5C6x%20%2B3%20%3D%206x%20%2B3%5C%5C6x-6x%2B3%20%3D%203%5C%5C3%20%3D%203)
<u>3(2x+1)=2(1+3x)-1</u>
![3(2x+1)=2(1+3x)-1\\6x+3 = 2+6x-1\\6x+3=1+6x\\6x-6x+3 = 1\\3 = 1](https://tex.z-dn.net/?f=3%282x%2B1%29%3D2%281%2B3x%29-1%5C%5C6x%2B3%20%3D%202%2B6x-1%5C%5C6x%2B3%3D1%2B6x%5C%5C6x-6x%2B3%20%3D%201%5C%5C3%20%3D%201)
<u></u>
<u>3(2x-1)=2(1+3x)-1</u>
![3(2x-1)=2(1+3x)-1\\6x-3 = 2+6x-1\\6x-3 = 1+6x\\6x-6x-3 = 1\\-3 = 1](https://tex.z-dn.net/?f=3%282x-1%29%3D2%281%2B3x%29-1%5C%5C6x-3%20%3D%202%2B6x-1%5C%5C6x-3%20%3D%201%2B6x%5C%5C6x-6x-3%20%3D%201%5C%5C-3%20%3D%201)
<u></u>
<u>3(2x+1)=2(3+2x)-3</u>
![3(2x+1)=2(3+2x)-3\\6x+3 = 6+4x-3\\6x+3 = 3+4x\\6x-4x+3 = 3\\2x+3 = 3](https://tex.z-dn.net/?f=3%282x%2B1%29%3D2%283%2B2x%29-3%E2%80%8B%5C%5C6x%2B3%20%3D%206%2B4x-3%5C%5C6x%2B3%20%3D%203%2B4x%5C%5C6x-4x%2B3%20%3D%203%5C%5C2x%2B3%20%3D%203)
The following equation has infinite many solutions
3(2x+1)=2(1+3x)+1
Keywords: Solution of equation, Linear equation
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24/40 = 12/20 = 6/10 = 3/5 Answer is C
Idk use Socratic but if not cry cuz math sucks
(–c^2)^3*.15c^4
power to a power in exponents is multiply
(–c^2)^3 = (-c^ 6)
= -c^6
-c^6 *.15 c^4
when multiply exponents add the exponents , multiply the coefficients
(-1*.15)c^(6+4)
=-.15 c^(10)