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leva [86]
1 year ago
8

12. (ST5) The weight of a bag of chips isapproximately normally distributed with amean of 10.72 oz. and a standard deviationof 0

.14. What is the probability that arandomly selected bag of chips is less thanthe advertised weight of 10.5 oz.?
Mathematics
1 answer:
kenny6666 [7]1 year ago
8 0

μ = mean = 10.72 oz

σ =standard deviation = 0.14

x = 10.5

First, find the z-score:

z = x - μ / σ

z = (10.5 - 10.72) / 0.14 = -1.57143

Then find the value on the z-score table:

P (x < 10.5) = 0.058042

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18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

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Answer:

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Step-by-step explanation:

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We know that 1 year have 52 weeks. We get

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