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timama [110]
3 years ago
9

How do you calculate the Hypotenuse?

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0
Formula:
a^2+b^2=c^2

c^2: Is the hypotenuse.

For  a^2 and b^2, you have to multiply both it by its self.

Then, add both.

Next, you square root it.

Example:

a^2+b^2=c^2

14^2+7^2=c^2

196+49=c^2

245=c^2

15.64=c^2
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fomenos

Answer:

The answer could be A

Step-by-step explanation:

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3 years ago
|x - 1| > 4 is equivalent to which of the following?
Vsevolod [243]

Answer:

C. x > 5 or x < - 3

Step-by-step explanation:

  • |x - 1| > 4

Step 1:

x - 1 > 4

x > 4 + 1

x > 5

Step 2:

x - 1 < -4

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HP: {x > 5 or x < -3} (c)

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Serga [27]

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Counting my money

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the product?
Tanzania [10]

Answer:

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

Step-by-step explanation:

\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}

Multiply the row of the first matrix to the column of the second matrix

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\

=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}

simplifying them we get

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

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3 years ago
The value of the varriable which satisfies the equation is called the _______ of the equation​
scoray [572]

Answer:

solution

Step-by-step explanation:

solution is the answer

3 0
3 years ago
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