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weqwewe [10]
1 year ago
10

Why are some r groups nonpolar, some polar, and others electrically charged(acidic or basic)?

Chemistry
1 answer:
aliina [53]1 year ago
3 0

On the basis of the characteristics of the "R" group in each amino acid, amino acids can be divided into four general groupings. Polar, nonpolar, electrically charges amino acids are all possible types. The "R" groups on polar amino acids are hydrophilic, meaning they want to come into touch with watery solutions.

What are amino acids?

Organic compounds known as amino acids join with other amino acids to produce proteins. Because the proteins that amino acids create are involved in almost all cellular processes, amino acids are necessary for life. While some proteins serve as structural support, others act as antibodies or enzymes. Although there are hundreds of amino acids in nature, only a set of 20 amino acids are used to make proteins.

On the basis of the characteristics of the "R" group in each amino acid, amino acids can be divided into four general groupings. Polar, nonpolar, electrically charges amino acids are all possible types. The "R" groups on polar amino acids are hydrophilic, meaning they want to come into touch with watery solutions. The hydrophobic (opposite) nonpolar amino acids shy away from contact with fluids. These interactions are crucial for protein folding and provide proteins with their three-dimensional structure.

To learn more about amino acids from the given link below,

brainly.com/question/14649293

#SPJ4

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Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)
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Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

S.G=\frac{D}{d_w}

d_w = density of water = 1 g/mL

D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = \frac{Mass}{Density}

=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L

1 mL = 0.001 L

Molarity = \frac{n}{V(L)}

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L

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