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Chemistry

2 answers:

mixer [17]3 years ago

5 0

Answer:

E: When an animal/organism dies their remains go into the ground which fertilize the ground

F: When plants moisture gets put into the atmosphere to make rain

B: When clouds provide mineral to feed plants

Vedmedyk [2.9K]3 years ago

4 0

Explanation:

B: The plants take the CO₂ and turns it into O (oxygen)

F: The process of respiration in plants involves using the sugars produced during photosynthesis plus oxygen to produce energy for plant growth. respiration takes place in the mitochondria of the cell in the presence of oxygen

E: Most organisms become fossils when they're changed through various other means. This process which is called carbonization, or distillation yields a detailed carbon impression of the dead organism in sedimentary rock

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For the reaction

sp2606 [1]

Answer:

$n_{H_2}^{equilibrium}=0.393mol$

Explanation:

Hello,

In this case, given the amounts of water and carbon dioxide we should invert the given reaction as hydrogen will be producted rather than consumed:

$H_2O(g) + CO(g)\rightleftharpoons H_2(g) + CO_2(g)$

Consequently, the equilibrium constant is also inverted:

$Kc'=\frac{1}{Kc}=\frac{1}{0.534} =1.87$

In such a way, we can now propose the law of mass action:

$Kc'=\frac{[H_2][CO_2]}{[H_2O][CO]}$

And we can express it in terms of the initial concentrations of the reactants and the change $x$ due to the reaction extent:

$Kc'=\frac{(x)(x)}{([H_2O]_0-x)([CO]_0-x)}=1.87$

Thus, we compute the initial concentration which are same, since equal amount of moles are given:

$[H_2O]_0=[CO]_0=\frac{0.680mol}{70.0L}=0.0097M$

Hence, solving for $x$ by using the quardratic equation or solver, we obtain:

$x_1=0.00561M\\x_2=0.0361M$

For which the correct value is 0.00561M since the other one will produce negative concentrations of water and carbon monoxide at equilibrium. Therefore, the number of moles of hydrogen at equilibrium for the same 70.0-L container turn out:

$n_{H_2}^{equilibrium}=0.00561mol/L*70.0L=0.393mol$