The amount remaining at the end of 5 half-lives is 7.81×10¹³ g
From the question given above, the following data were obtained:
- Half-life (t½) = 5730 years
- Original amount (N₀) = 2.5×10¹⁵ g
- Number of half-lives (n) = 5
- Amount remaining (N) =?
The amount remaining can be obtained as follow:
N = 1/2ⁿ × N₀
N = 1/2⁵ × 2.5×10¹⁵
N = 1/32 × 2.5×10¹⁵
N = 0.03125 × 2.5×10¹⁵
N = 7.81×10¹³ g
Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g
Learn more about half-life: brainly.com/question/25783920
Answer:
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Answer:
Volume of bacteria cell into Pico liters = 60.27 Pico liters
Explanation:
Given:
Volume of bacteria cell = 6.027 x 10⁻¹⁰ L
Find:
Volume of bacteria cell into Pico liters
Computation:
1 L = 10¹² Pico liters
So,
Volume of bacteria cell = 6.027 x 10⁻¹⁰ L
Volume of bacteria cell = 6.027 x 10⁻¹⁰ x 10¹² Pico liters
Volume of bacteria cell into Pico liters = 60.27 Pico liters
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