Question

Write an equation in standard form of the line that passes through the given point and has the given slope (I need an answer ASAP please)
1. (4, -1); m = 3

2. (-8, 0); m = -4

3. (-6, -10); m = 1/6

Answer 1

The equation of the lines is,

1. (4, -1); m = 3 : - y = 3x - 13

2. (-8, 0); m = -4 :- y = -4x - 24

3. (-6, -10); m = 1/6 :- y = -1/6x - 9

What is an equation of the line?

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

The equation of the lines will be,

y = mx + c

y = 3x + c

-1 = 4 x 3 + c

c = -13

y = 3x - 13

y = mx + c

y = -4x + c

0 = -4 x -8 + c

c = -24

y = -x -24

y = mx + c

y = 1/6x + c

-10 = -1 + c

c = -9

y = -1/6x - 9

Therefore, the equation of the lines is,y = 3x - 13 y = -4x - 24 and y = -1/6x - 9.

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