Answer:
12 years
Step-by-step explanation:
Represent the mother's age by m and the son's by 4. Currently m = 36 years old.
In x years the mother will be three times as old as her son:
mother: 36 + x years old
son: 4 + x years old
The pertinent equation to solve is:
36 + x = 3(4 + x)
Performing the multiplication, we get:
36 + x = 12 + 3x, or
24 = 2x. Then x = 12.
Check: In 12 years, will the mother's age be 3 times the son's age?
Does 36 + 12 = 3(4 + 12)?
Does 48 = 48? YES
The mother will be 3 times as old as her son in 12 years from now.
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
Answer:
- -2/a³ m/s
- -2 m/s
- -1/4 m/s
- -2/27 m/s
Step-by-step explanation:
The velocity is the derivative of position:
v = ds/dt = (d/dt)(t^-2) = -2t^-3
For t=a, the velocity is
-2a^-3 = -2/a³ . . . . meters per second
For t=1, the velocity is ...
-2·1³ = -2 . . . . meters per second
For t=2, the velocity is ...
-2·2^-3 = -2/8 = -1/4 . . . . meters per second
For t=3, the velocity is ...
-2·3^-3 = -2/27 . . . . meters per second
Answer:
C
Step-by-step explanation:
Hope this helps
First, let's make these two into equations.
The first plan has an initial fee of $40 and costs an additional $0.16 per mile driven.
Our equation would then be
C = 40 + 0.16m
where C is the total cost, and m is the number of miles driven.
The second plan has an initial fee of $51 and costs an additional $0.11 per mile driven.
So, the equation is
C = 51 + 0.11m
where C is the total cost, and m is the number of miles driven.
Now, your question seems to be asking for one mileage for both, equalling one cost. I would go through all the steps I've taken to try and find this for you, but it would probably take hours to type out and read. In short, I'm not entirely sure that an answer like that is possible in this situation, simply because of the large difference in the initial fee of the two plans, along with the sparse common multiples between the two mileage costs.
