I need help please ASAP
1 answer:
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Answer:
range = 7.87
X = 62.12, X²= 164.3516
mean = 1.2424
variance = 1.779
standard deviation = 1.33379
coefficient of variation = 107.3559%
Step-by-step explanation:
a.) The range =
highest number - lowest number
= 7.89 - 0.02
= 7.87
b.) from the attachment I solved for X and X²
∑X = 62.12
∑X² = 164.3516
c.)
the mean = ∑x/n
n = 50
= 62.12/50
= 1.2424
variance =
σ² = [∑x²-(∑x)²/n] / n-1
= [164.3516 - (62.12)²/50] / 50-1
= 164.3516 - 77.17788/49
= 87.173712/49
= 1.779
standard deviation = √σ
= √1.779
= 1.33379
d. coefficient of variation
= σ/mean * 100
= 1.33379/1.2424 * 100
= 107.3559
This number tells us that the the standard deviation of the time to failure is larger than the average time. option 3 is the correc4 answer here
