Question

find the equation of the axis of symmetry for this equation. f(x) = 6x^2 - 3x + 49. hint: to find the axis of symmetry, use equation: x = -b/2a

Answer 1

We want to find the axis of symmetry of the function;

$f(x)=6x^2-3x+49$

STEP 1:

The equation for the axis of symmetry of a line is given as;

$x=-\frac{b}{2a}$

From the equation, a = 6 and b = -3, so,

STEP 2: Insert the values of a and b into the equation to obtain;

$x=-\frac{-3}{2\times6}=--\frac{3}{12}=+\frac{1}{4}$

CONCLUSION:

Therefore, we see that the axis of symmetry is the line;

$x=\frac{1}{4}$