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o-na [289]
1 year ago
13

find the equation of the axis of symmetry for this equation. f(x) = 6x^2 - 3x + 49. hint: to find the axis of symmetry, use equa

tion: x = -b/2a
Mathematics
1 answer:
Olenka [21]1 year ago
8 0

We want to find the axis of symmetry of the function;

f(x)=6x^2-3x+49

STEP 1:

The equation for the axis of symmetry of a line is given as;

x=-\frac{b}{2a}

From the equation, a = 6 and b = -3, so,

STEP 2: Insert the values of a and b into the equation to obtain;

x=-\frac{-3}{2\times6}=--\frac{3}{12}=+\frac{1}{4}

CONCLUSION:

Therefore, we see that the axis of symmetry is the line;

x=\frac{1}{4}

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