Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
15, 28, 41.
add the common difference to each consecutive term to find the next term in the sequence.
2+ 13= 15
15+ 13= 28
28+ 13= 41
Answer:
Right skewed Histogram.
Explanation:
As the peak of the graph lies to the left side of the centre.
Answer:
Step-by-step explanation:
Parts of the question are missing.
y = a(x-h)² + k is a vertical parabola.
If a is positive, the parabola opens upwards.
If a is negative, the parabola opens downwards.
The vertex is at (h, k)
Answer:
x-13=0
Step-by-step explanation:
