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SCORPION-xisa [38]
1 year ago
14

Helpppp this assignment is due in like 30 minutessss

Mathematics
1 answer:
topjm [15]1 year ago
3 0
Answer is -17/4 P+25
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Alex paid $20,448 for a new car. He will make equal payments each month or 4 years. What will be Alex's monthly car payment
fgiga [73]

Answer:

$426

Step-by-step explanation:

According to the question,

New car cost = $20,448

Time to repay = 4 years or 48 months

So, we can calculate the monthly car payment by using following formula,

Monthly car payment = New car cost ÷ Time to repay

By putting the value, we get

Monthly car payment = $20,448 ÷ 48

= $426

Hence, Alex monthly car payment is $426.

5 0
3 years ago
What the min, max, lower quartile, upper quartile, and median on the photo.
Pie

Answer:

Minimum: 14 Maximum: 87.5 Lower Quartile: 34  Upper Quartile: 65  Median: 47.5

Step-by-step explanation:

3 0
3 years ago
At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The sta
Tamiku [17]

At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The statistician reported that the mean serve speed of a particular player was 95 miles per hour. Suppose that the statistician indicated that the serve speed distribution was skewed to the left. Which of the following values is most likely the value of the median serve speed? Explain your answer.

C) 77 mph

5 0
4 years ago
Find lim h->0 f(9+h)-f(9)/h if f(x)=x^4 a. 23 b. -2916 c. 2916 d. 2925
Svetach [21]

\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = \lim_{h\to0}\frac{(9+h)^4-9^4}h

Carry out the binomial expansion in the numerator:

(9+h)^4 = 9^4+4\times9^3h+6\times9^2h^2+4\times9h^3+h^4

Then the 9⁴ terms cancel each other, so in the limit we have

\displaystyle \lim_{h\to0}\frac{4\times9^3h+6\times9^2h^2+4\times9h^3+h^4}h

Since <em>h</em> is approaching 0, that means <em>h</em> ≠ 0, so we can cancel the common factor of <em>h</em> in both numerator and denominator:

\displaystyle \lim_{h\to0}(4\times9^3+6\times9^2h+4\times9h^2+h^3)

Then when <em>h</em> converges to 0, each remaining term containing <em>h</em> goes to 0, leaving you with

\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = 4\times9^3 = \boxed{2916}

or choice C.

Alternatively, you can recognize the given limit as the derivative of <em>f(x)</em> at <em>x</em> = 9:

f'(x) = \displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h \implies f'(9) = \lim_{h\to0}\frac{f(9+h)-f(9)}h

We have <em>f(x)</em> = <em>x</em> ⁴, so <em>f '(x)</em> = 4<em>x</em> ³, and evaluating this at <em>x</em> = 9 gives the same result, 2916.

8 0
3 years ago
Distribute 2 (9x^2 + 3).
beks73 [17]

Answer:

18x^2+6

Step-by-step explanation:

2(9x^2+3)

multiply each term in parentheses by 2

2 x 9x^2+2 x 3

calculate product

18x^2+2 x 3

multiply numbers

18x^2+6

5 0
3 years ago
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