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xxTIMURxx [149]
2 years ago
13

Please help thx 10 poin

Mathematics
1 answer:
Annette [7]2 years ago
7 0

Answer:

X = 55

Step-by-step explanation:

If the angel is 90:

75 + 90 = 165

165 divided by 3 = 55

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Plz help on rationalising surds
Fittoniya [83]
(√5 + 3)² / √20=
((√5 + 3)² / √20)(√20/√20)=
(√20(√5 + 3)²) / (√20)²=
√20(5+6√5+9) /20=
√20 (14+6√5) /20=
(14√20 +6√100) /20=
(14√20 +60) / 20=
(14(√4√5) + 60) /20=
(14(2)(√5)+60) / 20=
(28√5+60) /20=
(7√5+15) / 5

Answer:(√5 + 3)² / √20= <span>(7√5+15) / 5</span>
3 0
2 years ago
each morning, danai buys breakfast on her why to work. In the past thirty days, she bought a bagel on 6 days, a banana on 12 day
Ksju [112]

Answer:

  • 0.7 or 70%

Step-by-step explanation:

Total number of days

  • 6 + 12 + 3 + 9 = 30

The number of days she bought a banana or orange

  • 12 + 9 = 21

The probability of buying a banana or an orange is

  • P(b or o) = 21/30 = 0.7 = 70%
8 0
2 years ago
!HELP! Which expression is equivalent to the given expression? (10c^6 d^-5) (2c^-5 d^4)
Aliun [14]

Answer: 2343

Step-by-step explanation:

8 0
3 years ago
What’s the total value of the 6 in 26,312
Orlov [11]
The total value is 6,000
5 0
3 years ago
Read 2 more answers
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
3 years ago
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