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2 years ago

30 points Please help will mark brainliest.

Mathematics

1 answer:

Solnce55 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

To draw a perpendicular to line L we will use the following steps.

1). We will use the compass first. We will put the compass at the point P and draw an arc which will intersect the line L at two distinct points.

2). Now we will again draw two arcs by taking same measurement in compass

so that these arcs intersect each other.

3). Now we will joint the point of intersection formed by the arcs to the point P with the help of ruler.

In this way we get the line perpendicular to line L.

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(FIRST PERSON TO ANSWER GETS BRAINLIEST!!!) A student earned $2500.75 at his summer job making $12.50 per hour. Let h represent

laiz [17]

<u>Answer:</u>

$12.50 \space\ h = 2500.75$

<u>Step-by-step explanation:</u>

We know from the question that the student earned $12.50 <em>per hour</em>.

Using this information, we can say that if the student worked for <em>h </em>hours, they would make a total of 12.50 × <em>h </em>dollars.

We also know that the total money they earned is $2500.75.

∴ Therefore, we can set up the following equation:

$\boxed {12.50 \times h = 2500.75}$

From here, if we want to, we can find the number of hours worked by simply making <em>h</em> the subject of the equation and evaluating:

<em>h </em>=<em> </em> $\frac{2500.75}{12.50}$

= 200.6 hours

5 0

1 year ago

Read 2 more answers

10 1/2 * 10 1/2 simplify

Marta_Voda [28]

$\frac{441}{4}$

change the mixed numbers to improper fractions and multiply the numerators / denominators

10 $\frac{1}{2}$ = $\frac{21}{2}$

$\frac{21}{2}$ × $\frac{21}{2}$ = $\frac{441}{4}$ = 1110 $\frac{1}{4}$

4 0

2 years ago

Will mark brainliest for the correct answer!

romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0

2 years ago

One case of books weighs 35 pounds one case of magazine weighs 23 pounds a bookstore wants to ship 72 cases of books and 94 case

Sati [7]

you multiply 35 to 72 to get 2520 and then multiply 23 to 94=2139 add both of the answers to get 4659

7 0

2 years ago

Solve sin2x + 2sinx = 0 for 0 ≤ x < 2π. ...?

IgorC [24]

Sin 2 x + 2 sin x = 0
2 sin x cos x + 2 sin x = 0 / : 2
sin x cos x + sin x = 0
sin x ( cos x + 1 ) = 0
sin x = 0, cos x + 1 = 0, cos x = - 1;
Answer:
x = 0, or x = π

3 0

2 years ago