All categories

1 year ago

Which of these nonterminating decimals can be converted into a rational number?

Mathematics

1 answer:

VARVARA [1.3K]1 year ago

7 0

The non-terminating decimal that can be converted into a rational number is given by:

0.321321321.

<h3>What are rational and irrational numbers?</h3>

Rational numbers are numbers that can be represented by fractions, with examples such as numbers that have no decimal parts, or numbers in which the decimal parts are terminating or repeating.

Irrational numbers are numbers that cannot be represented by fractions, being non-terminating and non-repeating decimals, such as non-exact square roots, and the most common example of an irrational number is the number pi = 3.1415....

In the context of this problem, we are given four non-terminating decimal numbers, in which the only one with a repeating decimal pattern is:

0.321321321...

In which the pattern is:

321.

Hence the number can be written as the following rational number = fraction:

321/999.

With 999 being due to the fact that the repeating pattern is composed by three digits.

More can be learned about rational numbers at brainly.com/question/12088221

#SPJ1

You might be interested in

Various problems with data collection can cause some observations to be missing. Suppose a data set has 20 cases. Here are the v

mr Goodwill [35]

Answer:

a) Mean= 15, standard deviation= 5.1575

b) Mean= 15, standard deviation= 3.6469

c) See below

Step-by-step explanation:

(a) Compute the mean and standard deviation for the 10 cases for which x is not missing.

The mean using the ten known values is

$\bar x=\frac{17+6+12+14+20+23+9+12+16+21}{10}=15$

The standard deviation is

$\small s=\sqrt{\frac{(17-15)^2+(6-15)^2+(12-15)^2+(14-15)^2+(20-15)^2+(23-15)^2+(9-15)^2+(12-15)^2+(16-15)^2+(21-15)^2}{10}}=5.1575$

(b) Create a new data set with 20 cases by using imputation where you set the values for the 10 missing cases equal to the mean that you computed in the previous part. Compute the mean and standard deviation for this new data set with 20 cases.

The new data set would be

17, 6, 12, 14, 20, 23, 9, 12, 16, 21, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15

The new mean for this set of values would be then

$\bar x=\frac{\displaystyle\sum_{i=1}^{20}x_i}{20}=15$

The new standard deviation is now

$s=\sqrt{\frac{\displaystyle\sum_{i=1}^{20}(x_i-\bar x)^2}{20}}=3.6469$

(c) Summarize what you have learned about the possible effects of this type of imputation on the mean and the standard deviation.

Obviously, this way of imputation is somewhat arbitrary and will produce a set of data undoubtedly skewed.

It could possibly be a sensible way of imputing data if the amount of missing data is very little compared to the whole set, for example one or two data in a set of 100, but in this case we have 50% of missing data and it makes no sense this procedure.

4 0

3 years ago

This month Jan saved $80 from her babysitting job. Last month she saved $20. How many times more did she save this month than la

Ede4ka [16]

Answer:

4 times more

Step-by-step explanation:

80/20=4

6 0

3 years ago

For the inverse variation function y = k/x (where x, k > 0), what happens to the value of y as the value of x increases?

Allisa [31]