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Alexeev081 [22]
1 year ago
14

I need some help on this question. I sent a screenshot on this.

Mathematics
1 answer:
morpeh [17]1 year ago
4 0

Answer: 1/2

Step-by-step explanation:

I'm assuming this is rise over run. The rise is 1 and the run is 2.

Remember, \frac{rise}{run}

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19/25 which is likely

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What is the result of 72 divided by 12? 6 8 9 12
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3 years ago
Given 3 and 1 over 10 times negative six times 5 over 12, determine the product.
Finger [1]

3\frac{1}{10} \times -6\cdot \cfrac{5}{12}\implies \cfrac{3\cdot 10+1}{10} \times \cfrac{-6\cdot 5}{12}\implies \cfrac{31}{10}\times \cfrac{-6}{12}\cdot 5\implies \cfrac{31}{10}\times \cfrac{-1}{2}\cdot 5 \\\\\\ \cfrac{31}{10}\times \cfrac{-5}{2}\implies \cfrac{31\cdot -5}{10\cdot 2}\implies \cfrac{-155}{20}\implies -7\frac{3}{4}

6 0
2 years ago
Triangle ABC with vertices A (-1, 4), B( -4, 1), and C(-1, 1) is reflected across the y-axis and then translated 4 units to the
Anna71 [15]

Given:

Triangle ABC with vertices A (-1, 4), B( -4, 1), and C(-1, 1) is reflected across the y-axis and then translated 4 units to the left to form triangle A’B’C’.

To find:

The coordinates of the vertices of triangle A’B’C’.

Solution:

If triangle ABC reflected across y-axis, then

(x,y)\to (-x,y)

A(-1,4)\to A_1(1,4)

B(-4,1)\to B_1(4,1)

C(-1,1)\to C_1(1,1)

Coordinates of image after reflection across y-axis are A_1(1,4),B_1(4,1),C_1(1,1).

Then triangle translated 4 units to the left to form triangle A’B’C’.

(x,y)\to (x-4,y)

A_1(1,4)\to A'(-3,4)

B_1(4,1)\to B'(0,1)

C_1(1,1)\to C'(-3,1)

Therefore, the vertices of triangle A’B’C’ are A’ (-3, 4), B’ (0, 1), C’ (-3, 1).

Hence, the correct option is B.

6 0
3 years ago
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