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elena55 [62]
3 years ago
5

(please help) List the three lowest numbers that have the following characteristics. Work must be shown. 60 is a multiple of the

number 3 is a factor of the number 4 is not a factor of the number
Mathematics
1 answer:
Paul [167]3 years ago
6 0

Answer:

3, 6, and 15

Step-by-step explanation:

Notice that if 60 is a multiple, the numbers in question could have the same factors as 60.

So let's look at 60's prime factors:

60 = 2 * 2 * 3 * 5

we also know that 3 is a factor, so the factor 3 must be included in all three options, we also know that 4 is NOT a factor, so both factors 2 cannot be included (but only one of them could).

So, in order to build the lowest possible numbers that verify such conditions, we can use:

3

3 * 2 = 6

since 3 or 2 cannot be repeated, the next smaller would be:

3 * 5 = 15

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In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0
3 years ago
20 The table shows the linear relationship between the balance of a student's
Pavlova-9 [17]

Answer:7

Step-by-step explanation:it’s 7

7 0
3 years ago
In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha
olga55 [171]

In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid  meteor:

1 + \frac{1}{5}  \\ \\ = 1 + 0.2 \\  \\ = 1.2

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

x = \frac{525600}{1.2}

x = 438000

∴  438,000 meteors fell during the Perseid shower.

For  Leonid meteor shower:

4 + \frac{2}{3} = 4.67

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that  fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

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3 years ago
Plz answer then explain how did you did it
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Answer:

subtract the exponents:

a^7-2=a^5

Step-by-step explanation:

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valina [46]

Answer:133

Step-by-step explanation:

7 0
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