Answer:
3, 6, and 15
Step-by-step explanation:
Notice that if 60 is a multiple, the numbers in question could have the same factors as 60.
So let's look at 60's prime factors:
60 = 2 * 2 * 3 * 5
we also know that 3 is a factor, so the factor 3 must be included in all three options, we also know that 4 is NOT a factor, so both factors 2 cannot be included (but only one of them could).
So, in order to build the lowest possible numbers that verify such conditions, we can use:
3
3 * 2 = 6
since 3 or 2 cannot be repeated, the next smaller would be:
3 * 5 = 15
