Answer:
??
Step-by-step explanation:
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
Step-by-step explanation:
9
1. ∠ACB ≅∠ECD ; vertical angles are congruent (A)
2. C is midpoint of AE ; given
3. AC ≅CE; midpoint divides the line segment in 2 congruent segments (S)
4.AB║DE; given
5. ∠A≅∠E; alternate interior angles are congruent (A)
6. ΔABC≅ΔEDC; Angle-Side-Angle congruency theorem
10
1. YX≅ZX; given (S)
2. WX bisects ∠YXZ; given
3. ∠YXW≅∠ZXW; definition of angle bisectors (A)
4. WX ≅WX; reflexive propriety(S)
5. ΔWYX≅ΔWZX; Side-Angle-Side theorem