The expectation, E(3y +2) and variance, Var(3y+2) of the random variable are 13.4 and 19.44 respectively
<h3>How to determine the expectation and variance of a random variable?</h3>
The expectations or expected value E(y) of a random variable can be thought of as the “average” value of the random variable. It is also called its mean
By definition:
if y = ax + b
then E(y) = aE(x) + b
where a,b = constant
The variance V(y) of a random variable is the measure of spread for the distribution of a random variable that determines the degree to which the values of a random variable differ from the expected value
By definition
if y = ax + b
V(b) = 0
V(y) = V(ax) + V(b)
= a²V(x) + 0
where a,b = constant
Given: E(y)= 3.8 and Var(y)= 2.16
Calculate E( 3y +2) and Var( 3y+ 2)
E(3y +2) = 3E(y) + 2 since E(y) = 3.8
= 3×3.8 + 2
= 11.4+2
= 13.4
Var(3y+2) = 3²Var(y) + 0
= 9×2.16
= 19.44
Therefore, E(3y +2) is 13.4 and Var(3y+2) is 19.44
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