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QveST [7]
4 years ago
12

Can someone please explain how I do this. My teacher is kinda useless.

Mathematics
2 answers:
givi [52]4 years ago
6 0
<span>when the altitude is </span>drawn from the vertex of the right angle<span> of a right triangle to its hypotenuse, the altitude equals the product</span> of the two segments of the hypotenuse<span>.
(w+9)</span>²=8*18=144
w+9=12 or w+9=-12
w=3 (discard the negative number)

use the same method, z=√(9*11)=3√11

next, you can use the Pythagorean theorem to find x and y.
x=√(9²+99)=√180=6√5
y=√(11²+99)=√220=2√55
SOVA2 [1]4 years ago
5 0
Omgggg I really hate my math teacher to go he talks to fast and don’t makes sense like lol
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Give your answer in its simplest form.
andrew-mc [135]

Answer:

Is the question to develop the equation for the straight line shown?

If so,<u> y = (3/4)x + b</u>

Step-by-step explanation:

Look for an equation with the form y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).

Calculate Slope using the Rise/Run.

Pick any two points.  I chose (-4,0) and (4,6).

Going from left to right:

Rise = (6 - 0) = 6

Run = (4 - (-4)) = 8

Slope is Rise/Run, 6/8 or 3/4

So we have:  y = (3/4)x + b

We can see that the y-intercept, b, is 3 (the value of y when x = 0).

The full equation becomes :<u>  y = (3/4)x + 3 </u>

3 0
3 years ago
At 3 a.M. The temperature is -5 degrees Fahrenheit between 3 a.M. And 6 a.M. The temperature dropped by 12 degrees Fahrenheit be
LuckyWell [14K]

What I would do is subtract 12 from -5. Then you would have -17. Then you would add 4 and it would be -13. So your answer is:

<h2><em>-13</em></h2>

8 0
4 years ago
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Please help please and thank you
Katyanochek1 [597]

Step-by-step explanation:

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3 years ago
Solve the question ​
Nastasia [14]

Answer:

the answer is 402 the 2 lines just make the answer an even number and if its already even nothing happens

Step-by-step explanation:

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HELP plZZZZZZZ<br> and THANK YOU
Artyom0805 [142]

\huge \bf༆ Answer ༄

Let's solve ~

Y - intercept of the line is the point where value of x is 0 [ where the line cuts y - axis ]

\qquad \leadsto\sf \: (0 , 3)

X - intercept of the line is at the point where value of y is 0

[ where the line cuts x - axis ]

\qquad \leadsto\sf \: (1 , 0)

3 0
2 years ago
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