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Snezhnost [94]
3 years ago
5

Which is the solution to the inequality below?

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0
Remember

|a|≥0 for all real values of a


so
|x-2|+4≤3
minus 4 both sides
|x-2|≤-1
false, absolute value can never be negative
no solution
a is answer
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You take out a 60-day loan for $5000. At the end of the loan, you owe $73.97 in interest. What is the annual percentage rate? Ro
gulaghasi [49]

The PERCENTAGE ANNUAL RATE is 9.0% to the nearest tenth using the SIMPLE INTEREST FORMULA

The question is related to a SIMPLE INTEREST problem:

Loan period = 60 days

using 365 days a year ;

converting to years , 60 days = (60 / 365) years

interest on loan = 73.97

principal = 5000

Using the formula:

interest = (principal * rate * time)

73.79 = (5000 * rate * (60/365)

Rate = 73.79/(5000 * (60/365)) =8.977%

rate = 9%

Therefore, PERCENTAGE ANNUAL RATE is 9.0%

8 0
3 years ago
Heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp
crimeas [40]

Answer:

0.6 - 1/4

Convert the decimal to fraction

Thus

0.6 = 3/4

3/5 - 1/4

Find the LCM

the LCM is 20

We get

3/5 - 1/4 = (3(4) - 5)/ 20

= 12-5/20

= 7/20

2/5 + 0.75

0.75 = 3/4

Find the LCM

The LCM is 20

Thus

3/4 +2/5 = ( 3(5) + 2(4))/20

= 15 + 8 /20

= 23 / 20 or 1 3/20

1.75 - 1/6

Convert the decimal to fraction

1.75 = 7/4

Thus we get

7/4 - 1/6

Find the LCM

The LCM is 12

Thus

7/4 - 1/6 = ( 7(3) - 2)/12

= 21 - 2 / 12

= 19/ 12 or 1 7/12

3/10 + 2.125

Convert the decimal to fraction

2.125 = 17/8

Thus

3/10 + 17/8

Find the LCM

the LCM is 40

Thus

3/10 + 17/8 = ( 3(4) + 17(5))/40

= 12 + 85/40

= 97 /40 or 2 17/40

Hope this helps

8 0
3 years ago
Read 2 more answers
Help me please this is 7th grade math
kodGreya [7K]

Answer:

A = 113. 097

Step-by-step explanation:

A = πr^2

A = π6^2

A = π x 36

8 0
4 years ago
Read 2 more answers
Find the volume of the solid generated by revolving the area bounded by y=x^2 and x-axis from [0,2] around the x-axis
lesya [120]

Answer:  \dfrac{32\pi }{5}\ \text{unit}^3

Step-by-step explanation:

Given

The area is bounded by y=x^2 and x-axis from [0,2]

The volume generated for y=f(x) when rotated about the x-axis in the interval [a,b] is

V=\int_a^b\pi y^2dx

Insert the values

\Rightarrow V=\int_0^2\pi x^4dx\\\\\Rightarrow V=\pi \int_0^2x^4dx\\\\\Rightarrow V=\pi \left[ \dfrac{x^5}{5}\right]_0^2\\\\\Rightarrow V=\dfrac{2^5\pi }{5}\\\\\Rightarrow V=\dfrac{32\pi }{5}\ \text{unit}^3

8 0
3 years ago
Can someone help me out What is the solution to the system graphed?
ozzi

Answer:

1,-2

Step-by-step explanation:

I BELEIVE THAT IS IT BECAUSE IT MEETS AT 1 THEN GOES UP TO -2 WHICH MAKES

1,-2

3 0
3 years ago
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