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deff fn [24]
1 year ago
11

5. Find the circumcenter of the triangle. XXX CU 3 (4,2) KNNYA XHENNARO 3 ****************++++++ 5 NET Virtual cla 44,-3) WHEREw

hat is answer

Mathematics
1 answer:
Elan Coil [88]1 year ago
8 0

The circumcenter of a right angled triangle is midpoint of the hypotenuse side.

Determine the midpoint of the hypotenuse.

\begin{gathered} x=\frac{-4+0}{2} \\ =\frac{-4}{2} \\ =-2 \end{gathered}

For y coordinate,

\begin{gathered} y=\frac{2-3}{2} \\ =\frac{-1}{2} \end{gathered}

So, circumcenter of triangle is,

(-2,\frac{-1}{2})

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The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $⁢1800, which was to be divided equally among t
CaHeK987 [17]
Let's say "p" people were going to the expedition initially, and the cost for each was "c", now, we know the total cost is 1800, so for "p",  folks that'd be  1800/p how much each one cost, namely, how many times "p" goes into 1800.

well, prior to leaving, 15 dropped out, so that leaves us with " p - 15 ", and the cost "c" bumped up to " c + 27 " for each.

\bf \begin{cases}
\cfrac{1800}{p}=\boxed{c}\\\\
\cfrac{1800}{p-15}=c+27\\\\
----------\\
\cfrac{1800}{p-15}=\boxed{\cfrac{1800}{p}}+27
\end{cases}\\\\
-------------------------------\\\\
\cfrac{1800}{p-15}={\cfrac{1800}{p}}+27\impliedby 
\begin{array}{llll}
\textit{let's multiply both sides by}\quad  p(p-15)\\
\textit{to get rid of the denominators}
\end{array}

\bf 1800p=1800(p-15)+27[p(p-15)]
\\\\\\
1800p=1800p-27000+27(p^2-15p)
\\\\\\
0=-27000+27(p^2-15p)\implies 0=-27000+27p^2-405p
\\\\\\
\textit{now, let's take a common factor of }27
\\\\\\
0=p^2-15p-1000\implies 0=(p-40)(p+25)\implies p=
\begin{cases}
\boxed{40}\\
-25
\end{cases}

well, you can't have a negative value of people... so it has to be 40.

so, 40 folks were initially going, then 15 dropped out, how many went on the expedition?  40 - 15.
3 0
3 years ago
Special variables that hold copies of the values passed to functions are called
JulsSmile [24]
You would call those arguments.
4 0
3 years ago
What are the ordered pairs of the solutions for the
Likurg_2 [28]

Answer:

(3,1) ; (6,-2)

Step-by-step explanation:

We have to search the points that the line and the parabola have in common, that are the points where they intercept

(3,1) ; (6,-2)

8 0
3 years ago
Solve 2X squared plus X equals 15
Karo-lina-s [1.5K]

Answer:

x=5

Step-by-step explanation:

2x+x= 3x

3x=15

15/3=5

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME I RESLLY NEED HELP
Lynna [10]
Basically it’s like 40x10 and then let’s say your exponent is two so you would do that equation twice so it would be 800
4 0
4 years ago
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