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Greeley [361]
3 years ago
12

The answer please I need the answers

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

I think you need to multiply 12 and 7 and then cut that in half

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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the stand
Mrrafil [7]
Y= x-11   bc...
y-1=x-12
 +1   +1
y=x-11

5 0
3 years ago
What did susan have for dinner?<br> A.Statistical <br> B.Non-statistical
abruzzese [7]
Answer: Non-Statistical
4 0
3 years ago
I-Ready
Tpy6a [65]

Answer:

The Answer is #2

Step-by-step explanation:

I took the quiz

6 0
3 years ago
What is the distance between point A and point B? Round to nearest tenth.
Sergeu [11.5K]

Answer:

d \approx 12.6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point A (-4, 2)

Point B (8, 6)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

  1. Substitute [DF]:                    d = \sqrt{(8+4)^2+(6-2)^2}
  2. Add/Subtract:                       d = \sqrt{(12)^2+(4)^2}
  3. Exponents:                           d = \sqrt{144+16}
  4. Add:                                      d = \sqrt{160}
  5. Simplify:                                d = 4\sqrt{10}
  6. Evaluate:                              d = 12.6491
  7. Round:                                 d \approx 12.6
7 0
3 years ago
To get an estimate of consumer spending over a holiday season in 2009, 436 randomly sampled American adults were surveyed. Their
Tatiana [17]

Answer:

<em>-A 90% confidence interval would be narrower than the 95% confidence interval if we don't need to be as sure about our estimate. </em>

<em>-This confidence interval is not valid since the distribution of spending in the sample data is right skewed.</em>

<em>-The margin of error is $4.4.</em>

<em>-This confidence interval is valid since the sampling distribution of sample mean would be approximately normal with sample size of 436.</em>

<em>-We are 95% confident that the average spending of all American adults over this holiday season is between $80.31 and $89.11.</em>

<em />

Step-by-step explanation:

<em>A 90% confidence interval would be narrower than the 95% confidence interval if we don't need to be as sure about our estimate. </em>

TRUE. The 90% confidence is less strict in its probability of having the mean within the interval, so it is narrower than the 95% CI. It relies more in the information given by the sample.

<em />

<em>In order to decrease the margin of error of a 95% confidence interval to a third of what is is now, we would need to use a sample 3 times larger. </em>

FALSE. The margin of error is z*σ/(n^0.5). So to reduce it by two thirds, the sample size n needs to be 3^2=9 times larger.

<em>This confidence interval is not valid since the distribution of spending in the sample data is right skewed.</em>

FALSE. There is no information about the skewness in the sample.

<em>The margin of error is $4.4.</em>

TRUE. The margin of error is (89.11-80.31)/2=$4.4.

<em>We are 95% confident that the average spending of these 435 American adults over this holiday season is between $80.31 and $89.11.</em>

FALSE. The CI is related to the populations mean. We are 95% confident that the average spending of the population is between $80.31 and $89.11.

<em>This confidence interval is valid since the sampling distribution of sample mean would be approximately normal with sample size of 436.</em>

TRUE. This happens accordingly to the Central Limit Theorem.

<em>95% of random samples have a sample mean between $80.31 and $89.11.</em>

FALSE. The confidence interval refers to the population mean.

<em>We are 95% confident that the average spending of all American adults over this holiday season is between $80.31 and $89.11.</em>

TRUE. This is the conclusion that is looked for when constructing a confidence interval.

6 0
4 years ago
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