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1 year ago

Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1

Mathematics

1 answer:

lana [24]1 year ago

8 0

We assume that the function is as follows:

$f^{-1_{}}(2)=?$

Then, we have that:

$f^{-1}(x)=\frac{1}{f(x)}$

Thus, if we have that:

$f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}$

Therefore, the value for the function is f^-1(2) = -1/2 or

$f^{-1}(2)=-\frac{1}{2}$

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3 years ago

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erastovalidia [21]

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0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

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At most 3 including an order, which is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

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