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MrRa [10]
1 year ago
5

If f(x) = 3x22, evaluate afI: ()k=1

Mathematics
1 answer:
Korolek [52]1 year ago
5 0

Step 1: Write out the function given

f(x)=3x^2-x

Step 2: Interprete the question given

\sum ^5_{k\mathop=1}f(\frac{k}{2})

The question requested we find the summation of the first five terms for f(k/2), when k is 1, 2, 3, 4, and 5

Step 3: Find the expression for f(k/2)

\begin{gathered} f(\frac{k}{2})=3(\frac{k}{2})^2-\frac{k}{2} \\ =\frac{3k^2}{4}-\frac{k}{2} \\ =\frac{3k^2-2k}{4} \end{gathered}\begin{gathered} =\frac{3(1)^2-2(1)}{4}+\frac{3(2)^2-2(2)}{4}+\frac{3(3)^2-2(3)}{4}+\frac{3(4)^2-2(4)}{4}+\frac{3(5)^2-2(5)}{4} \\ =\frac{1+8+21+40+65}{4} \\ =\frac{135}{4} \\ =33.75 \end{gathered}

Hence, the answer is 33.75

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How to do this. Can you maybe show me your work?
Musya8 [376]
VX = 204
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204/3= 68
68*2= 136
VW= 136, XW= 68
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#7
Find the midpoint of each side. (0,2) (7,4) m1=(3.5,3)
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3 years ago
2a2 + -1 2-a) +36 ; a=5, b=0
salantis [7]

Answer:

the answer is 39

Step-by-step explanation:

hope that helps

3 0
3 years ago
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Can anyone walk me through this?
Fiesta28 [93]

Assuming that we are solving in terms of n.


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2(n + 5)

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2n + 10 = -2


Subtract 10 to start toward isolating your variable:

2n = -12


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6 0
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oksian1 [2.3K]

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3 years ago
➥ The base of a parallelogram is thrice its height. If the area is 897 sq.cm. Find the base and height of the parallelogram.
IgorC [24]

Answer:

The height of parallelogram is 51.87 cm

Step-by-step explanation:

Let The height of a parallelogram = a cm

Then

The base of a parallelogram = 3a cm

So by the given condition

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a = 17.29

So the height of parallelogram = 3×17.29= 51.87 cm

6 0
3 years ago
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