The diagram of the pentagon is missing, so i have attached it.
Answer:
|AE| = 130 m
|DE| = 150 m
Perimeter of pentagon = 720 m
Step-by-step explanation:
From the diagram, we can find AE from pythagoras theorem;
|AE| = √(|AA'|² + 50²)
Where AA' is the length from A to the perpendicular angle.
Now, AB = 150, and A'B is parallel to 30 m. Thus, A'B = 30
AA' = AB - A'B = 150 - 30
AA' = 120
Thus;
|AE| = √(120² + 50²)
|AE| = √(14400 + 2500)
|AE| = √16900
|AE| = 130
Similarly,
|DE| = √(|DD'|² + |ED'|²)
ED' = BC - 50
ED' = 140 - 50
ED' = 90
Also, DD' is parallel to AA' and is = 120
Thus;
|DE| = √(120² + 90²)
|DE| = √22500
|DE| = 150
Perimeter of pentagon = 150 + 130 + 150 + 150 + 140 = 720
Answer:
D
Step-by-step explanation:
y-y1=m(x-x1) through (4,4)
x-3y= -18 is perpendicular : m1*m2=-1
y=mx+c
-3y=-18-x
3y= 18+x
y=x/3 + 6
y= 1/3x + 6
m1*m2= -1
m1= -1/m2
m1= -1/1/3
m1= -3
y- 4= -3(x - 4)
y-4= -3x +12
y= -3x +12+4
y= -3x + 16
1,4,5,7 is quadratic and 2,3,6,8 is not a quadratic function. Check this out mate!