Answer:
-60
Step-by-step explanation:
The objective is to state whether or not the following limit exists
.
First, we simplify the expression in the numerator of the fraction.
Now, we obtain
and the fraction is transformed into
Therefore, the following limit is
You can plug in 
in the equation, hence
Easy, find the equation of the line,
Using y=mx+b form:
(-1,3) m=2
3= 2(-1)+b
3= -2+b
+2 +2
5=b
y=2x+5. This is your equation.
Now, plug in the coordinates:
(-3,2)
2= 2(-3)+5
2= -6+5
2= -1
NO
(0,5)
5= 2(0)+5
5=5
YES
(1,5)
5= 2(1)+5
5= 2+5
5=7
NO
(1,4)
4= 2(1)+5
4= 2+5
4=7
NO.
Thus, B, is your answer.
Answer:
c
d
Step-by-step explanation:
Answer:
<u>y = w and ΔABC ~ ΔCDE</u>
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90° ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
<u>∴ ∠x = ∠z </u>
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
<u>∴ ∠y = ∠w</u>
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C ⇒ proved by ∠y = ∠w
- ∠B = ∠D ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E ⇒ proved by ∠x = ∠z
So, from the previous ΔABC ~ ΔCDE by AAA postulate.
So, the answer is <u>y = w and ΔABC ~ ΔCDE</u>
