Find the slope of a line that passes through (4.5,3.5) and (9.5,5.5) M =

1 answer:

7 0

$(\stackrel{x_1}{4.5}~,~\stackrel{y_1}{3.5})\qquad (\stackrel{x_2}{9.5}~,~\stackrel{y_2}{5.5})~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5.5}-\stackrel{y1}{3.5}}}{\underset{run} {\underset{x_2}{9.5}-\underset{x_1}{4.5}}}\implies \cfrac{2}{5}$

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Use the graph to determine the vertex point of the quadratic function. Is the vertex a

Feliz [49]

Answer:

B) Vertex (1,2), maximum

Step-by-step explanation:

First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.

The maximum is the point that has the greatest y value. We can see that the greatest y value is at $y=2$ . Going down two units from that spot, we can see that the x value is at $x=1$ . We can plug those into the vertex form, $(x,y)$ . By plugging in we get the point $(1,2)$ .