Answer:

x = 45.6

Explanation:

-10(x + 21) = -15x + 18

-10x - 210 = -15x + 18

-210 = -5x + 18

-228 = -5x

x = 45.6

(I’m not sure if this is what you’re looking for, but I hope it helped a bit)

7 0

3 years ago

The ratios of the measure of the sides of a triangle is 4:10:7. Find the length of each side of the perimeter of the triangle is

dangina [55]

The given ratio of the sides of the triangles is 4:10:7. Let the sides be 4x, 10x and 7x .

And given perimeter is 252 meters .

Perimeter is the sum of all sides. So we get

$4x+10x+7x=252 \\ 21x = 252$

Dividing both sides by 21

$x = 12$

So the sides are

$4*12=48 meters \\ 10*12=120 meters \\ 7*12= 84 meters$

8 0

3 years ago

Read 2 more answers

A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The

Vladimir [108]

Using the Sine rule,

$\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}$ $\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}$

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

$A^0+P^0+B^0=180^0$ $\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}$

Using the side rule to find the length of wire BP,

$\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}$

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0

1 year ago