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xeze [42]
3 years ago
12

Can someone help me simplify this?

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0
=(14+3i) - (-12-7i) + (6+2i)
=14 + 3i +12 + 7i + 6 + 2i
=32 + 12i
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I need help I’m in math class! Help please
AVprozaik [17]

Answer:

1350π cm^3 should be your answer

Step-by-step explanation:

15 x 15 x π = 225π

225π x 6 = 1350π

7 0
3 years ago
Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
Marina deposits $1,500 in a savings account at Bank of America. The bank will pay her 5% interest at the end of the year. How mu
AURORKA [14]

Answer:

75 of additional money

Step-by-step explanation:

5% of 1,500 is 75

and 1,500 plus 75 is 1575

5 0
3 years ago
The differential equation dy dx equals the quotient of the quantity x plus 1 and y minus 3
Phantasy [73]

Answer:

I only

Step-by-step explanation:

dy/dx = x + 1 / y -3

(y - 3)dy = (x + 1) dx

integrate

1/2y^2 - 3x = 1/2x^2 + x

1/2y^2 = 1/2x^2 + 4x

y^2 = x^2 + 8x

y = (x^2 + 8x)^1/2

3 0
3 years ago
Lucy and Emily are racing with each other and Lucy is 90
Zina [86]

Using the <em>system of equation</em> created, Emily will catch up Lucy after 30 seconds

Given the Parameters :

  • Lucy's distance = 2t
  • Emily's distance = 5t

<u>We can set up an equation to represent the required scenario thus</u> :

Emily's distance = Lucy's distance + 90

5t = 2t + 90

We solve for t

<em>Collect like terms</em> :

5t - 2t = 90

3t = 90

Divide both sides by 3 to isolate t

t = 90/3

t = 30

Therefore, Emily will catch up with Lucy after 30 seconds

Learn more :brainly.com/question/13218948

8 0
2 years ago
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