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AleksandrR [38]
3 years ago
6

How do you multiple the following (x-8)(x-7)

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0
You would need to cross multiply.  When you do that you get x^2-7x-8x+56.  Once simplifying you get x^2-15x+56.
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7th grade math help me please :(
coldgirl [10]

Answer:

<h2>92 remainder 280</h2>

Step-by-step explanation:

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Naya [18.7K]
It's a geometric sequence.

4,-12,36,... \\ \\&#10;a_1=4 \\&#10;r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\&#10;a_n=a_1 \times r^{n-1} \\&#10;a_n=4 \times (-3)^{n-1} \\&#10;a_n=4 \times (-3)^{-1} \times (-3)^n \\&#10;a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\&#10;a_n=-\frac{4}{3}(-3)^n

It's the sum for term 4 through term 15.

 \boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}
8 0
3 years ago
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ad-work [718]

Answer:

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3 0
3 years ago
Explain why f(x) = x2+4/x2-x-2 is not continuous at x = 2.
xxTIMURxx [149]

Answer: Option a.

Step-by-step explanation:

 Make the denominator equal to zero and solve for x:

Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:

x^{2}-x-2=0\\(x-2)(x+1)=0\\x=2\\x=-1

Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2

The answer is the option a.

6 0
3 years ago
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