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3 years ago

PLEASE HELP IM SO CONFUSED!!!

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

7 0

The slope means that they raise $2 pet every box sold. You can find this by how many it increases (2) and how many it moves to the right (1) so $2 per 1 box

adoni [48]3 years ago

5 0

Answer:

$2 per box

Step-by-step explanation:

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The function G(x)=f(x+3)+2 which of the following is true of the graph of g(x)?

zepelin [54]

G(x)=(x+3)+2

G(x) = (x-h) + k
h translates the graph left/right and k translates the graph up/down.
Because the equation is x- the parenthesis is (x - - 3) which makes h a negative 3 and will translate left. The k positive so it will move up.
Letter B

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3 years ago

What is 0.316 in expanded form.

RUDIKE [14]

Uhm, I'm pretty new to expanded form but I think it's something like:
(3 × 1/10) + (1 × 1/100) + (6 × 1/1000)
You can also write it as:
0.3 + 0.01 + 0.006
Let me know if you need working or anything!

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4 years ago

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Can you plz help me plz

Harman [31]

Answer:b=16

Step-by-step explanation:trust me bro

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3 years ago

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Find a5 when a1 = 2, r = 2

mihalych1998 [28]

I think your answer is 32

4 0

3 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

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3 years ago